A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

I saw someone using this in one answer: void methodA(const int*& var); I couldn't understand what the argument means. AFAIK: const int var => const int value which can't …

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process …

7 c is a double variable, but the value being assigned to it is an int value because it results from the division of two int s, which gives you "integer division" (dropping the remainder). So what …

Jan 28, 2013 · int array[] = new int[10]; ? Both do work, and the result is exactly the same. Which one is quicker or better? Is there a style guide which recommends one?

Dec 17, 2013 · │int││int││int││int││int││int││ └───┘└───┘└───┘└───┘└───┘└───┘└┄ Of course, there's no reason they can't all …

Mar 29, 2012 · 3 Every expression in C or C++ has a type, a value, and possible side-effects. int i; ++i; The type of ++i is int. The side-effect is to increment i. The value of the expression is the …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

Dec 29, 2022 · For INT and other numeric types that attribute only specifies the display width. See Numeric Type Attributes in the MySQL documentation: MySQL supports an extension for …